function one after another

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1

Hi i have function and want it works 3 times after i click button. Unfortunatelly it works once or when i write without “then” 3 times but values dont change because funcion goes too quick. Does anybody can take a look. Thanks

function dodajestol(){
$w(“#dataset1”).onReady( () => {
let count = $w(“#dataset1”).getTotalCount();

$w(“#dataset1”). new ()
.then(() => {

$w(“#dataset1”).setFieldValue(“miejsce”, count+101);
return $w(“#dataset1”).save();
})
.then(() => {
$w(“#dataset1”).refresh();
console.log(“New item saved”);
})

})}

export function button64_click(event) {
$w(‘#button64’).disable()
dodajestol()
.then(() => {
dodajestol()
})
.then(() => {
dodajestol()
})
.then(() => {
$w(‘#button64’).enable();
})
}

2

Maybe you should try this. I do not think the promises and updates.

export function button64_click(event) {
 $w('#button64').disable()
 runFunction(3);  
 $w('#button64').enable();
 
}
let counter = 0;
export function runFunction(times) {
 if (counter < times) {
 dodajestol()
       .then(() => { 
 counter++;
 runFunction(times)
       });
    }
 
}

I also think you are missing a return inside the returned promise like below.

function dodajestol(){
 $w("#dataset1").onReady( () => {
 let count = $w("#dataset1").getTotalCount();
 
 $w("#dataset1").new()
 .then(() => {  
 
 $w("#dataset1").setFieldValue("miejsce", count+101);
 return $w("#dataset1").save();
  })
  .then(() => {
 $w("#dataset1").refresh();
 console.log("New item saved");
 return; // this one
  }) 
 
  })}

If you don’t have that you will return before the promise has been resolved.

3

it gives me error in .then line

TypeError: Cannot read property ‘then’ of undefined

export function button64_click(event) {
$w(’ #button64 ‘).disable() runFunction(3);
$w(’ #button64 ').enable(); }
let counter = 0; export function runFunction(times) {
if (counter < times) { dodajestol()
.then(() =>
{ counter++; runFunction(times) }); } }