hi everyone!!
I’m trying to make appear a ‘‘servicelistWidget’’ depending on wich ‘‘dropdown’’ value change.
I’d tried puthing this code :
import wixData from ‘wix-data’;
export function dropdown1_change(event, $w) {
$w(“#dataset1”).setFilter( wixData.filter()
.contains(“frais,local”, $w(‘#dropdown1’).value)
);$w(‘#serviceListWidget2’).show();
);$w(‘#serviceListWidget3’).show();
But it doenst seem to work… any advice on how i can make it appear seperatly?
Thank you!!!
Hi Keenan,
You need to be a little clearer about the logic that will govern which widget will show.
I noticed that the field key in your setFilter condition, “frais,local”, has a comma in it. Commas cannot be included in field keys, so that can’t be the correct field key.
hi!
in fact all i need is that a #servicewidgetlist appear when a selection is made in the dropdown.
So differtent Dropdown ‘‘value’’ = Different #servicewidget list that appear.
i don’t know if it’s help you at all?
Thanks for the help 
If you simply want some a element to be shown depending on a dropdown value choice, then you can simply find your answer already in previous forum posts.
https://www.wix.com/corvid/forum/community-discussion/dropdown-selection-to-show-elements
Thanks! it really helped me!
Now
I would like to know what to do to add several values for the same query in the formula below:
export function dropdown1_change (event, $ w) {
let value = event.target.value;
if (value === ‘fild1’) { ****** Here I would like to have other values for the same result ******
W $ ( ‘# serviceListWidget2’) show ().
W $ ( ‘# serviceListWidget1’) hide ().
W $ ( ‘# columnStrip3’) hide ().
When I just add with quotes it does not work … I am therefore forced to copy the formulas for all scenarios. 15 times …
Is there probably something simpler?