How to add data from different fields into One dropdown list?

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1

$w.onReady( () => {
$w( “#dataset1” ).onReady( () => {
let itemObj1 = $w( " #dataset1" ).getCurrentItem( “field1” );
let itemObj2 = $w( " #dataset1" ).getCurrentItem( “field2” );
let itemObj3 = $w( " #dataset1" ).getCurrentItem( “field3” );
$w( “#ipbox” ).options = [
{ “label” : itemObj1, “value” :itemObj1.toString()},
{ “label” : itemObj2, “value” :itemObj1.toString()},
{ “label” : itemObj3, “value” :itemObj1.toString()},
]

} );
The main problem is how to get the data from a specific field of one item.
itemObj1 = $w( " #dataset1" ).getCurrentItem( “field1” );
I tried this way, but it did not work… Hope someone can help me… Thank a lot! :sob:

2

Hello

try to do it like this one…

$w.onReady( () => {  $w("#dataset1").onReady( () => {let itemObj1 = $w("#dataset1").getCurrentItem().titlelet itemObj2 = $w("#dataset2").getCurrentItem().title    console.log(itemObj1)    console.log(itemObj2)let myOptions = [        {"label": itemObj1,"value":itemObj1.toString()},        {"label": itemObj2,"value":itemObj1.toString()},    ]    $w("#ipbox").options = myOptions  })})

In this example i used 2-different DATABASES.
You can also just use one DATABASE (by using just one DATASET).